March 2022 0 6 Report
Найдите тангенс угла наклона касательной, проведенной через точку А, к графику функции f(x): a) f(x) = 2x2 + 2, A(0; 2);​ СРОЧНО ПРОШУ!!!!!!
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.
More Questions From This User See All
d877db88043240088275b53b37fef29a
Answer
d2551857358cdc4cb1dfd4fbbffaf7e4
Answer
00d055bb4a6e65ac3941d000f6f120f1
Answer
6d35a3ef6b25588e6245ccbaf499bd35
Answer
pomogite proshudam 25 bvsyo chto est
Answer
4h4 5h0 1srochnoooo pomogite
Answer
travelling has become popular in recent years srochnooooooo pzh
Answer

Helpful Links

Helpful Social

Copyright © 2024 SCHOLAR.TIPS - All rights reserved.