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aleksandr2406
@aleksandr2406
August 2022
1
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Найдите точки экстремума функции y=x^2+2x-3
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NadDer
График функции - парабола, ветви вверх.
Значит, точки
max - нет
Найдем координаты вершины:
m = -b\2a
m = -2\2 = -1
n = (-1)^2+2*(-1)-3 = 1-2-3 = -4
(-1;
-4
)
Значит,
min = -4
2 votes
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Answers & Comments
Значит, точки max - нет
Найдем координаты вершины:
m = -b\2a
m = -2\2 = -1
n = (-1)^2+2*(-1)-3 = 1-2-3 = -4
(-1;-4)
Значит, min = -4