найдите точку максимума функции y=(x-6)^2(x+9)+3. Created by skellann. algebra-ru

найдите точку максимума функции y=(x-6)^2(x+9)+3...

skellann @skellann

July 2022 1 17 Report

найдите точку максимума функции y=(x-6)^2(x+9)+3

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sedinalana

Verified answer

Y`=2(x-6)(x+9)+1*(x-6)²=(x-6)(2x+18+x-6)=(x-6)(3x+12)=0
x=6 x=-4
+ _ +
----------------(-4)---------------(6)-----------------
max min
ymax=(-10)²*5+3=503
ymin=0*9+3=3

6 votes Thanks 7

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