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Bigenr2
@Bigenr2
August 2022
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Найдите точку минимума функции Y=x^3+5x^2+7x-5
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mmb1
Verified answer
Y=x^3+5x^2+7x-5
Y'=3x^2+10x+7=0
D=100-84=16
x12=(-10+-4)/6=-1 -14/6=-7/3
y(-1)=-1+5-7-5=-8 минимум
y(-7/3)=-343/27+5*49/9-49/3-5=-7
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Answers & Comments
Verified answer
Y=x^3+5x^2+7x-5Y'=3x^2+10x+7=0
D=100-84=16
x12=(-10+-4)/6=-1 -14/6=-7/3
y(-1)=-1+5-7-5=-8 минимум
y(-7/3)=-343/27+5*49/9-49/3-5=-7