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danies
@danies
October 2021
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найдите третий коэффициент от начала в разложении бинома (x+y)^19
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MaggieDono
Формула разложения: (х+у)^n=x^n+nx^(n-1)y+(n(n-1))/(1*2)x^(n-2)b^2+...+(n(n-1)...(n-k+1))/(1*2*...*k)x^(n-k)y^k+...+nxy^(n-1)+y^n; ответ - 171*х^17*у^2
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