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dreakalex
@dreakalex
June 2022
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Найдите три первых члена геометрической прогрессии, у которой b3-b1=9, b5-b3=36
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eduardpavlenko
B3-b1=9
b5-b3=36
------------------
b3-b1=9
q^2*(b3-b1)=36
------------------
b1*(q^2-1)=9
q^2 = 4
------------------
q=2, b1=3
или
q=-2, b1=3
3, 6, 12, 24, 48...
12-3=9
48-12=36
3, -6, 12, -24, 48...
12-3=9
48-12=36
4 votes
Thanks 11
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Answers & Comments
b5-b3=36
------------------
b3-b1=9
q^2*(b3-b1)=36
------------------
b1*(q^2-1)=9
q^2 = 4
------------------
q=2, b1=3
или
q=-2, b1=3
3, 6, 12, 24, 48...
12-3=9
48-12=36
3, -6, 12, -24, 48...
12-3=9
48-12=36