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Egor149
@Egor149
July 2022
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Найдите угловой коэффициент касательной к графику функции F(x)=4eˣ в точке с абсциссой x₀=0
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hovsep50
К = F'(x =0)
F'(x) =(4e^x)' = 4e^x
k = 4e^0 = 4·1 = 4
2 votes
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Answers & Comments
F'(x) =(4e^x)' = 4e^x
k = 4e^0 = 4·1 = 4