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MisisJulia
@MisisJulia
July 2022
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Найдите угловой коэффициент касательной проведенной к графику функции y=корень из 3 cos x в точке с абсциссой x0=Пи
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ShirokovP
Verified answer
K = y ' (x0) = 0
y ' = √3 (cosx) ' = - √3 sinx
y ' (pi) = - √3 sin pi = - √3 * 0 = 0
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Verified answer
K = y ' (x0) = 0y ' = √3 (cosx) ' = - √3 sinx
y ' (pi) = - √3 sin pi = - √3 * 0 = 0