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Eva12345678910
@Eva12345678910
August 2021
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Найдите ∠В в треугольнике с вершинами А(−1; 0), В(1; 2√3),
(1; 0).
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sedinalana
Verified answer
AB=√(1+1)²+(2√3-0)²=√(4+12)=√16=4
BC=√(1-1)²+(0-2√3)²=√(0+12)=2√3
AC=√(1+1)²+(0-0)²=√2
cos<B=(AB²+BC²-AC²)/(2AB*BC)
cos<B=(16+12-2)/(2*4*2√3)=26/16√3=13√3/24
<B=arccos(13√3/24)≈20гр
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Answers & Comments
Verified answer
AB=√(1+1)²+(2√3-0)²=√(4+12)=√16=4BC=√(1-1)²+(0-2√3)²=√(0+12)=2√3
AC=√(1+1)²+(0-0)²=√2
cos<B=(AB²+BC²-AC²)/(2AB*BC)
cos<B=(16+12-2)/(2*4*2√3)=26/16√3=13√3/24
<B=arccos(13√3/24)≈20гр