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oleg27042000
@oleg27042000
July 2022
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Найдите вершины
y=2x^2+4x-6
y=-3x^2+12x-5
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Answers & Comments
lmatem
1) х(вершина)=-в/2а=-4/2*2=-1, y(вершина)=2*(-1)^2+4*(-1)-6=-8, (-1;-8)
2) х(вершина)=-12/2*3=-2, y(вершина)=3*(-2)^2+12*(-2)-5=-17, (-2;-17)
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Answers & Comments
2) х(вершина)=-12/2*3=-2, y(вершина)=3*(-2)^2+12*(-2)-5=-17, (-2;-17)