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paknosy2002
@paknosy2002
August 2022
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Найдите значение буквенного выражения:
1) (19-7б)+(9б-8); б=1;2
2)(5а-3)+(8а+16); 3а=1;2;3;
3)28-с3; c=12,24
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zoo15
1) (19-7×1)+(9*1-8)=13
1)(19-7×2)+(9×2-8)=15
2) (5×1-3)+(8*1+16)=26
2) (5*2-3)+(8*2+16)=39
2) (5*3-3)+(8*3+16)=52
третий низнаю
3 votes
Thanks 4
Эрик2117
1)(19-7б)+(9б-8)=(19-7×1)+(9×1-8)=12+1=13.(б=1)
1)(19-7б)+(9б-8)=(19-7×2)+(9×2-8)=5+10=15.(б=2)
2)(5а-3)+(8а+16)=(5×1-3)+(8×1+16)=2+24=26(а=1)
2)(5×2-3)+(8×2+16)=7+32=39.(а=2)
2)(5×3-3)+(8×3+16)=12+40=52.(а=3)
3)28-с3=28-12×3=28-36=-8.(с=12)
3)28-с3=28-24×3=28-72=-44
1 votes
Thanks 1
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Answers & Comments
1)(19-7×2)+(9×2-8)=15
2) (5×1-3)+(8*1+16)=26
2) (5*2-3)+(8*2+16)=39
2) (5*3-3)+(8*3+16)=52
третий низнаю
1)(19-7б)+(9б-8)=(19-7×2)+(9×2-8)=5+10=15.(б=2)
2)(5а-3)+(8а+16)=(5×1-3)+(8×1+16)=2+24=26(а=1)
2)(5×2-3)+(8×2+16)=7+32=39.(а=2)
2)(5×3-3)+(8×3+16)=12+40=52.(а=3)
3)28-с3=28-12×3=28-36=-8.(с=12)
3)28-с3=28-24×3=28-72=-44