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Alyachka007
@Alyachka007
August 2022
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найдите значение корня
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uekmyfhfp
A^2 - b^2 =(a+b)(a - b)
1. sgrt(313^2 - 312^2) =sgrt((313-312)(313+312))= sgrt(1*625)= sgrt1* sgrt625 = 1*25 = 25;
2. sgrt(117^2 - 108^2)= sgrt((117 - 108)(117 + 108))=sgrt(9*225)= sgrt9*sgrt225= =3*15=45.
4 votes
Thanks 2
Alyachka007
во 2 примере не написано же что кв.корень 117 и 108 в квадратах
uekmyfhfp
ну если не написано, то получаем просто корень квадратный из 9, что равно 3
aidanakosbayeva
√( 313-312) (313+312) =√645 = 25
1 votes
Thanks 1
uekmyfhfp
sgrt625 = 25
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Answers & Comments
1. sgrt(313^2 - 312^2) =sgrt((313-312)(313+312))= sgrt(1*625)= sgrt1* sgrt625 = 1*25 = 25;
2. sgrt(117^2 - 108^2)= sgrt((117 - 108)(117 + 108))=sgrt(9*225)= sgrt9*sgrt225= =3*15=45.