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chicca2013
@chicca2013
July 2022
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найдите значение параметра а если парабола y=x^2-a^2x+4a-13 проходит через точку A(1;-8)
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m11m
Verified answer
Y=x² - a²x +4a -13
A(1; -8)
x=1 y= -8
-8=1² - a² * 1 +4a -13
-8=1 - a² + 4a -13
-8= -a² + 4a -12
a² - 4a +12 -8 =0
a² - 4a +4 =0
(a-2)² =0
a-2=0
a=2
Ответ: 2.
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Answers & Comments
Verified answer
Y=x² - a²x +4a -13A(1; -8)
x=1 y= -8
-8=1² - a² * 1 +4a -13
-8=1 - a² + 4a -13
-8= -a² + 4a -12
a² - 4a +12 -8 =0
a² - 4a +4 =0
(a-2)² =0
a-2=0
a=2
Ответ: 2.