Найдите значение производной функции у=(t^4-3)(t^2+2) в точке tнулевое=1
у = (t^4-3)(t^2+2)
у' = (t^4-3)' *(t^2+2) + (t^2+2)' * (t^4-3)
у' = 4t³ * (t²+2) + (t^4-3)* 2t подставляем t = 1
у'(1) = 4*(1+2) + (1-3)*2 = 12 - 4 = 8
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у = (t^4-3)(t^2+2)
у' = (t^4-3)' *(t^2+2) + (t^2+2)' * (t^4-3)
у' = 4t³ * (t²+2) + (t^4-3)* 2t подставляем t = 1
у'(1) = 4*(1+2) + (1-3)*2 = 12 - 4 = 8