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tema9500
@tema9500
July 2022
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Найдите значение выражение 5-2sin^2x-1 если cos^2x=0,8
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nKrynka
5 - 2sin²x - 1 = 5 - 2(1 - cos²x) - 1 = 2 + 2cos²x
cos²x = 0,8
2 + 2*(0,8) = 2 + 1,6 = 3,6
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Answers & Comments
cos²x = 0,8
2 + 2*(0,8) = 2 + 1,6 = 3,6