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laeay
@laeay
July 2022
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hraky
1) (a^(1/2) * a^(1/3))^6=(a^(5/6))^6=a^5
a=(3⁻¹)^(2/5)=3^(-2/5)
a^5=(3^(-2/5))^5=3^(-2)=1/9
2) (a^(1/4) * a^(1/3))^12=(a^(7/12))^12=a^7
a=(3/4)^(2/7)
a^7=((3/4)^(2/7))^7=(3/4)^2=9/16
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Answers & Comments
a=(3⁻¹)^(2/5)=3^(-2/5)
a^5=(3^(-2/5))^5=3^(-2)=1/9
2) (a^(1/4) * a^(1/3))^12=(a^(7/12))^12=a^7
a=(3/4)^(2/7)
a^7=((3/4)^(2/7))^7=(3/4)^2=9/16