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MARUSIA2003SEMENOVA
@MARUSIA2003SEMENOVA
August 2022
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Найдите значение выражения 3(4a-b)^2-2(a-b)(a+b)+4(a+3b)^2 при=-0.2 b=-1
^-это степень
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sharadi
Verified answer
3(4a-b)^2 - 2(a-b)(a+b) + 4(a+3b)^2 при=-0.2 b=-1
(4a - b)
² = 16a² - 8ab + b²
(a - b0(a + b) = a² - b²
(a + 3b)² = a² + 6ab + 9b²
сам пример: 3(16a² - 8ab + b²) -2(a² - b²) + 4(a² + 6ab + 9b²)=
=48a²
-24ab
+3b² - 2a² + 2b² + 4a² +
24ab
+36b² =
= 50a² + 41b²
50a² + 41b² = 50*(-0,2)² + 41*(-1)² = 50*0,04 - 41 =2 - 41 = -39
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Verified answer
3(4a-b)^2 - 2(a-b)(a+b) + 4(a+3b)^2 при=-0.2 b=-1(4a - b)² = 16a² - 8ab + b²
(a - b0(a + b) = a² - b²
(a + 3b)² = a² + 6ab + 9b²
сам пример: 3(16a² - 8ab + b²) -2(a² - b²) + 4(a² + 6ab + 9b²)=
=48a² -24ab +3b² - 2a² + 2b² + 4a² + 24ab +36b² =
= 50a² + 41b²
50a² + 41b² = 50*(-0,2)² + 41*(-1)² = 50*0,04 - 41 =2 - 41 = -39