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DianaSavinova03
@DianaSavinova03
August 2022
1
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Найдите значение выражения 3cos^2 150° -4sin(90°) - 5stg135°
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Санечка69
Verified answer
3cos
²
150° - 4sin90° - 5
с
tg135° = 3
·cos²60° - 4·1 - 5· (-tg45°) = 3·1/4 -4 + 5·1 = =3/4 - 4 + 5 = 1 целая 3/4
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Verified answer
3cos² 150° - 4sin90° - 5сtg135° = 3·cos²60° - 4·1 - 5· (-tg45°) = 3·1/4 -4 + 5·1 = =3/4 - 4 + 5 = 1 целая 3/4