найдите значение выражения cos 990
cos990=cos(4п-450)=cos450=cos(2п+90)=cos90=0
990-360-360=270cos270=cos3П/2=cos(180+90)=--cos90=0
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cos990=cos(4п-450)=cos450=cos(2п+90)=cos90=0
990-360-360=270
cos270=cos3П/2=cos(180+90)=--cos90=0