Найдите значение выражения (x-4y)^2+4y(2x-4y) при х=-3|5
(x-4y)^2+4y(2x-4y)=х²-8ху+16у²+8ху-16у²=х²
при х=-3\5
х²=(-3\5)²=9\25.
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(x-4y)^2+4y(2x-4y)=х²-8ху+16у²+8ху-16у²=х²
при х=-3\5
х²=(-3\5)²=9\25.