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okapaevt
@okapaevt
July 2022
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армения20171
arctg(-1)-arctg1=-aectg1-arctg1=-π/4-π/4=
-π/2
arcsin(-1/2)-arctg(√3)=-π/6-π/3=-π/2
arcsin(-1)-arccos(-√2/2)=
-π/2-(π-arccos√2/2)=-π/2-π+π/4=-5π/4
arcsin1+arcctg√3=π/2+π/6=2π/3
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Answers & Comments
-π/2
arcsin(-1/2)-arctg(√3)=-π/6-π/3=-π/2
arcsin(-1)-arccos(-√2/2)=
-π/2-(π-arccos√2/2)=-π/2-π+π/4=-5π/4
arcsin1+arcctg√3=π/2+π/6=2π/3