Найдите значение выражения. Created by alina200070. algebra-ru

Найдите значение выражения...

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$\displaystyle \tt \bigg(\frac{mn}{m^{2}-n^{2}}+\frac{n}{2n-2m}\bigg)\cdot\frac{m^{2}-n^{2}}{2n}=\\\\\\=\bigg(\frac{mn}{(m-n)(m+n)}-\frac{n}{2(m-n)}\bigg)\cdot\frac{(m-n)(m+n)}{2n}=\\\\\\=\frac{n(2m-m-n)(m-n)(m+n)}{2(m-n)(m+n)\cdot2n}=\frac{m-n}{4};\\\\\\npu \ \ \ m=6\frac{1}{2}; \ \ n=-1,5\\\\\\\frac{m-n}{4}=\frac{6,5+1,5}{4}=2;$

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sangers1959

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Ответ:

Объяснение:

1. (mn/(m²-n²))+n/(2n-2m)=(mn/((m-n)(m+n))-n/(2m-2n)=

=(2mn-n*(m+n))/(2*(m-n)(m+n))=n*(2m-m-n)/(2*(n-m)(n+m))=

=n*(m-n)/(2*(m²-n²)).

(n*(m-n)/(2*(m²-n²))*((m²-n²)/2n)=(m-n)/4=(6,5-(-1,5)/4=(6,5+1,5)/4=8/4=2.

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