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Dasha01738
@Dasha01738
July 2022
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sedinalana
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2√2сos²9π/2-8=2√2*(1+cos9π)/2-8=√2+√2cosπ=√2+√2*(-1)=√2-√2=0
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Verified answer
2√2сos²9π/2-8=2√2*(1+cos9π)/2-8=√2+√2cosπ=√2+√2*(-1)=√2-√2=0