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Sonehka98
@Sonehka98
July 2022
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barracuda1313
Х^6-1=(x³-1)(x³+1) (из правила а²-b²=(a-b)(a+b))
получаем
(х³-1)(х³+1)/(х³+1) * (х+1)/(х²+х+1)
(х³-1)/1 * (х+1)(х²+х+1)
упростим х³-1=(х-1)(х²+х+1) (из правила a³-b³=(a-b)(a²+ab+b²))
(x-1)(x²+x+1)/1 * (x+1)(x²+x+1)
(x-1)/1 * (x+1)/1
(x-1)(x+1)=
x²-1
x=2√3=√12
(√12)²-1=12-1=11
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Answers & Comments
получаем
(х³-1)(х³+1)/(х³+1) * (х+1)/(х²+х+1)
(х³-1)/1 * (х+1)(х²+х+1)
упростим х³-1=(х-1)(х²+х+1) (из правила a³-b³=(a-b)(a²+ab+b²))
(x-1)(x²+x+1)/1 * (x+1)(x²+x+1)
(x-1)/1 * (x+1)/1
(x-1)(x+1)=x²-1
x=2√3=√12
(√12)²-1=12-1=11