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lenatur
@lenatur
June 2022
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найдите значения х для которых числа х+1 ; 2х+1 ; х^2-3 образуют арифметическую прогрессию
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miron2077
Verified answer
2х+1-(х+1)=х²-3-(2х+1)
2х+1-х-1=х²-3-2х-1
х²-3х-4=0
D=9+16=(⁺₋5)²
х₁=(3+5)/2=4
х₂=(3-5)/2=-1
при х₁=4 и при х₂=-1
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Answers & Comments
Verified answer
2х+1-(х+1)=х²-3-(2х+1)2х+1-х-1=х²-3-2х-1
х²-3х-4=0
D=9+16=(⁺₋5)²
х₁=(3+5)/2=4
х₂=(3-5)/2=-1
при х₁=4 и при х₂=-1