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scrafton2525
@scrafton2525
August 2022
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Найдите значения выражения: а) 24a+47a+53a+76a, если a=47 б)128p-72p-28p, если p=11
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Кондидат
А=47
47(24+47+53+76)=47 х 200=9 400
р=11
11(128-72-28)=11 х 28=308
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scrafton2525
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Answers & Comments
47(24+47+53+76)=47 х 200=9 400
р=11
11(128-72-28)=11 х 28=308