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Foxyck
@Foxyck
August 2022
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Найдите знаменатель геометрической прогрессии (bn), если b1=3, b2+b3=60
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njhieyjdf
B2=b1*q=3q
b3=b1*q²=3q
²
b2+b3=60
3q+3q
²-60=0
D=3
²-4*3*(-60)=9+720=729=27
²
q1=(-3+27)\3*2=24\6=4
q2=(-3-27)\2*3=-30\6=-5
Ответ:q=4 или q=-5
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Answers & Comments
b3=b1*q²=3q²
b2+b3=60
3q+3q²-60=0
D=3²-4*3*(-60)=9+720=729=27²
q1=(-3+27)\3*2=24\6=4
q2=(-3-27)\2*3=-30\6=-5
Ответ:q=4 или q=-5