Найти 2 числа,сумма которых равна 1000,а 30% первого на 200 больше 20% второго
1)8002)200
800/100*30=240
200/100*20=40
0.3X = 0.2Y + 200
X+Y = 1000
X = 1000 - Y
0.3 (1000 - Y) = 0.2Y + 200
300 - 0.3Y = 0.2Y + 200
100 = 0.5Y
Y = 200
X = 800
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1)800
2)200
800/100*30=240
200/100*20=40
0.3X = 0.2Y + 200
X+Y = 1000
X = 1000 - Y
0.3 (1000 - Y) = 0.2Y + 200
300 - 0.3Y = 0.2Y + 200
100 = 0.5Y
Y = 200
X = 800