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RutaS
@RutaS
June 2022
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Найти a√a - b√b ,если √a-√b =3, ab=4
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korolevivan
1)a-b=2, ab = 3
a = 2+b
b(2+b) - 3 = 0
b^2 + 2b - 3 = 0
D = 2^2 +4*3 = 4+12 = 16
b1 = (-2 +4)/2 = 2/2 = 1
b2 = (-2-4)/2 = -6/2 = -3
a1 = 2+1 = 3
a2 = 2-3 = -1
(a1^3-b1^3) = 3^3 - 1^3 = 27 - 1 = 26
(a2^3-b2^3) = (-1)^3 - (-3)^3 = 1 - 27 = -26
2)
y=|a|x-4
-1 = 2|a| - 4
2|a| = 3
|a| = 3/2 = 1.5
a = +-1.5
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RutaS
Спасибо за решение,,но в ответе должно получится 45
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Answers & Comments
a = 2+b
b(2+b) - 3 = 0
b^2 + 2b - 3 = 0
D = 2^2 +4*3 = 4+12 = 16
b1 = (-2 +4)/2 = 2/2 = 1
b2 = (-2-4)/2 = -6/2 = -3
a1 = 2+1 = 3
a2 = 2-3 = -1
(a1^3-b1^3) = 3^3 - 1^3 = 27 - 1 = 26
(a2^3-b2^3) = (-1)^3 - (-3)^3 = 1 - 27 = -26
2)y=|a|x-4
-1 = 2|a| - 4
2|a| = 3
|a| = 3/2 = 1.5
a = +-1.5