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dimonbigbibon
@dimonbigbibon
August 2022
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найти Ac,если Ab=6 и bc=3 a угол A=30
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khayotjonovp7mn7o
BC/SIN30 = AB/SIN X 3/1/2=6/SINX ОТСЮДА Х = 90 ГРАДУСОВ
180-90-30=60. АС/SIN60=BC/SIN30=AB/SIN90 ОТСЮДА АС=6*SIN60= 3*КОРЕНЬ(3)
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180-90-30=60. АС/SIN60=BC/SIN30=AB/SIN90 ОТСЮДА АС=6*SIN60= 3*КОРЕНЬ(3)