Ответ:
Mr(K20) =Ar(K) +2Ab(O)=39+2*16=39+32=71
Mr(Fe203)=2Ar(Fe)+3(O)=2*56+3*16=112+48=160
Mr(HNO3)=Ab(H)+3Ar(N)+3Ar(O)=1+3*14+3*16=1+42+48=91
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Ответ:
Mr(K20) =Ar(K) +2Ab(O)=39+2*16=39+32=71
Mr(Fe203)=2Ar(Fe)+3(O)=2*56+3*16=112+48=160
Mr(HNO3)=Ab(H)+3Ar(N)+3Ar(O)=1+3*14+3*16=1+42+48=91