Дано:b3=2,b6=54/Найти b1(в геометрической прогрессии)
b[3]=2
b[6]=54
b[6]=b[5]q=b[4]qq=b[3]qqq=b[3]q^3
q^3=b[6]:b[3]
q^3=54:2
q^3=27
q=корень кубический(27)
q=3
b[1]=b[3]:q^2
b[1]=2:3^2=2/9
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b[3]=2
b[6]=54
b[6]=b[5]q=b[4]qq=b[3]qqq=b[3]q^3
q^3=b[6]:b[3]
q^3=54:2
q^3=27
q=корень кубический(27)
q=3
b[1]=b[3]:q^2
b[1]=2:3^2=2/9