найти частное(результат проверить умножением):(-4X^2-X+5):(4X+5)(6x^2+7x-3):(2x+3). Created by Dasha5555555666666. algebra-ru

найти частное(результат проверить умножением):(-4X^2-X+5):(4X+5)(6x^2+7x-3):(2x+...

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Verified answer

-4x²-x+5 | 4x+5
-4x²-5x     -x+1
     4x+5
     4x+5
          0
проверяем: (4x+5)(-x+1)=-4x²-5x+4x+5= -4x²-x+5

6x²+7x-3 | 2x+3
6x²+9x    3x-1
     -2x-3
     -2x-3
          0
проверяем: (2x+3)(3x-1)=6x²+9x-2x-3= 6x²+7x-3

2 votes Thanks 13

julyap $\frac{-4 x^{2} -x+5}{4x+5} \\ -4 x^{2} -x+5=0 /*(-1)\\ 4 x^{2} +x-5=0 \\ D=1+80=81 \\ \sqrt{D} =9 \\ x_{1} = \frac{-1+9}{8} = \frac{8}{8} =1 \\ x_{1} = \frac{-1-9}{8} = \frac{-10}{8} =-1.25 \\ 4x+5=0 \\ 4x=-5 \\ x=-1.25 \\ \frac{-4 x^{2} -x+5}{4x+5} = \frac{(x-1)(x+1.25)}{x+1.25} =x-1 \\ \\$

$2) \frac{6 x^{2} +7x-3}{2x+3} \\ 6 x^{2} +7x-3=0 \\ D=49+72=121 \\ \sqrt{D} =11 \\ x_{1} = \frac{-7+11}{12} = \frac{4}{12} = \frac{1}{3} \\ x_{2} = \frac{-7-11}{12} = \frac{-18}{12} =-1.5 \\ 2x+3=0 \\ 2x=-3 \\ x=-1.5 \\ \\ \frac{6 x^{2} +7x-3}{2x+3} = \frac{(x- \frac{1}{3} )(x+1.5)}{x+1.5} =x- \frac{1}{3}$

1 votes Thanks 2

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