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eozin
@eozin
July 2022
1
15
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Найти cos^6x-sin^6x, если cos2x=0,4
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Answers & Comments
avilov41
Решение:
cos^6x-sin^6x=(cos^2x)^3-(sin^2x)^3=
= ((1+cos(2x))/2)^3-((1-cos(2x))/2)^3=
= ((1+0,4)/2) ^3-((1-0,4)/2)^3=
=(0,7)^3-(0,3)^3=
=0,343-0,027=0,316.
Ответ: 0,316.
3 votes
Thanks 2
eozin
Спасибо!
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Answers & Comments
cos^6x-sin^6x=(cos^2x)^3-(sin^2x)^3=
= ((1+cos(2x))/2)^3-((1-cos(2x))/2)^3=
= ((1+0,4)/2) ^3-((1-0,4)/2)^3=
=(0,7)^3-(0,3)^3=
=0,343-0,027=0,316.
Ответ: 0,316.