-3х²+2x+1=0;

Для данного кв.уравнения: а= –3, b=2, c=1.

D= b²–4ac= 2²–4•(–3)•1= 4+12= 16= 4²

x1= (–b+√‎D)/2a= (–2+4)/2•(–3) = 2/(–6)= –⅓;

x2= (–b–√‎D)/2a= (–2–4)/2•(–3)= –6/(–6)= 1.

ОТВЕТ: –⅓ ; 1.