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tinabashkatova
@tinabashkatova
July 2022
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найти координаты центра и радиуса сферы, заданной уравнением x2+3x+y2-2y+z2+3=0
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mikael2
X²+3x=(x+1.5)²-2.25
y²-2y=(y-1)²-1
2.25+1-3=0.25
(x+1.5)²+(y-1)²+(z-0)²=0.5²
центр (-1,5; 1;0) R=0.5
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Answers & Comments
y²-2y=(y-1)²-1
2.25+1-3=0.25
(x+1.5)²+(y-1)²+(z-0)²=0.5²
центр (-1,5; 1;0) R=0.5