Найти корень: 3^(log27 (7x+1)) =4. Created by kotakot. matematika-ru

Найти корень: 3^(log27 (7x+1)) =4...

kotakot @kotakot

August 2022 1 11 Report

Найти корень: 3^(log27 (7x+1)) =4

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$27=3^3,\; \; log_{3^3}{(7x+1)}=\frac{1}{3}log_3{(7x+1)}=log_3{\sqrt[3]{7x+1}}\\\\3^{log_3{\sqrt[3]{7x+1}}}=4\\\\\sqrt[3]{7x+1}=4\\\\7x+1=4^3\\\\7x=64-1\\\\x=9$

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