найти корень уравнения Х-6 делёное на х-8 =3 дробь 2
2(x-6)=3(x-8)
2x-12=3x-24
x=24-12
x=12
(х - 6)/(х - 8) = 3/2
(х - 6)*2 = (х - 8)*3
2х - 12 = 3х - 24
х - 12 = 0
х = 12
Ответ: х = 12
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2(x-6)=3(x-8)
2x-12=3x-24
x=24-12
x=12
(х - 6)/(х - 8) = 3/2
(х - 6)*2 = (х - 8)*3
2х - 12 = 3х - 24
х - 12 = 0
х = 12
Ответ: х = 12