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August 2022
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Найти корень уравнения:
x-52-x2=3 б) 2y+12-4y2=5
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Aminka101102
X-52-x2=3
x^2-x+52=-3
x^2-x+52+3=0
x^2-x+55=0
D=1^2-4*1*55=-219
нет решений
2y+12-4y^2=5
4y^2-2y-12+5=0
4y^2-2y-6=0
D=4+4*4*6=100=10^2
x1=-(-2)+10
x1=12
x2=-(-2)-10
x2=-8
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Answers & Comments
x^2-x+52=-3
x^2-x+52+3=0
x^2-x+55=0
D=1^2-4*1*55=-219
нет решений
2y+12-4y^2=5
4y^2-2y-12+5=0
4y^2-2y-6=0
D=4+4*4*6=100=10^2
x1=-(-2)+10
x1=12
x2=-(-2)-10
x2=-8