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GrafMonteKristo4327
@GrafMonteKristo4327
November 2021
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найти корень уравнения x^3-8x^2+20x-16 15 баллов
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mmb1
Verified answer
x^3-8x^2+20x-16 = 0 (если равно 0)
преобразуем
x^3-4x^2-4x^2+16x+4x-16 = 0
x^2(x-4) - 4x(x-4) + 4(x-4) = 0
(x-4)(x^2-4x+4) = 0
(x-4)(x-2)^2=0
x=2
x=4
2 votes
Thanks 1
zumratzum
Verified answer
!!!!!!!!!!!!! посмотри!!!!!
0 votes
Thanks 1
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Answers & Comments
Verified answer
x^3-8x^2+20x-16 = 0 (если равно 0)преобразуем
x^3-4x^2-4x^2+16x+4x-16 = 0
x^2(x-4) - 4x(x-4) + 4(x-4) = 0
(x-4)(x^2-4x+4) = 0
(x-4)(x-2)^2=0
x=2
x=4
Verified answer
!!!!!!!!!!!!! посмотри!!!!!