Найти корень уравнения
№2log4(x+5)=log(4x-10)x+5=4x-103x= 15x=5№3log5(12-3x)=2+log5(3)log5(12-3x)-log5(3)=2log5(4-x)=24-x=25x=-21№44^(5x-13)=1/644^(5x-13)=4^-35x-13=-35x=10x=2№5(1/2)^(4x-11)=1/32(1/2)^(4x-11)=(1/2)^54x-11=54x=16x=4
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Answers & Comments
№2
log4(x+5)=log(4x-10)
x+5=4x-10
3x= 15
x=5
№3
log5(12-3x)=2+log5(3)
log5(12-3x)-log5(3)=2
log5(4-x)=2
4-x=25
x=-21
№4
4^(5x-13)=1/64
4^(5x-13)=4^-3
5x-13=-3
5x=10
x=2
№5
(1/2)^(4x-11)=1/32
(1/2)^(4x-11)=(1/2)^5
4x-11=5
4x=16
x=4