cos^2x+3sinx-3=0
1-sin^2x+3sinx-3=0
-sin^2x+3sinx-2=0
sinx=y
-y^2+3y-2=0
y^2-3y+2=0
D=1
y1=2
y2=1
sinx=1
x=П/2+2Пn
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
cos^2x+3sinx-3=0
1-sin^2x+3sinx-3=0
-sin^2x+3sinx-2=0
sinx=y
-y^2+3y-2=0
y^2-3y+2=0
D=1
y1=2
y2=1
sinx=1
x=П/2+2Пn
1-sin^2x+3sinx-3=0
sin^2x-3sinx+2=0
Пусть sinx=t, t [-1;1]
t^2-3t+2=0
D=9-8=1
t1=(3-1)/2=1
t2=2(не подходит)
sinx=1
x=П/2+2Пn, n∈Z