найти корни уравнения.(х-6)В квадрате=(7-х)В квадрате
(x-6)^2=(7-x)^2x^2-12x+36-49+14x-x^2=0
x^2-12x-13+14x-x^2=0
x^2+2x-13-x^2=0
2x-13=0
x=13/2x=6.5
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(x-6)^2=(7-x)^2
x^2-12x+36-49+14x-x^2=0
x^2-12x-13+14x-x^2=0
x^2+2x-13-x^2=0
2x-13=0
x=13/2
x=6.5