A=230 Qн=1000 η=? Qx=?
η=A/Qн=230/1000=0.23 (23%)
Qx=Qн-A=1000-230=770 кДж
=============
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A=230 Qн=1000 η=? Qx=?
η=A/Qн=230/1000=0.23 (23%)
Qx=Qн-A=1000-230=770 кДж
=============