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GarveL
@GarveL
July 2022
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Найти критические точки функции f(x)=x^3-3x
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Answers & Comments
amina381
F’(x)=3x^2-3
3x^2-3=0
3x^2=3
x^2=1
x=+-1
Xmax=-1
Xmin=1
Вроде бы так
2 votes
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Answers & Comments
3x^2-3=0
3x^2=3
x^2=1
x=+-1
Xmax=-1
Xmin=1
Вроде бы так