Ответ:
24+32+16*4=120
Mg: 24/120 = 20%
S: 32/120 = 26,67%
O: 64/120 = 53,33%
Объяснение:
M(MgSO4)=24+32+16*4=120
W(Mg)=24/120=20,2%
W(S)=32/120=26,6%
W(O)=64/120=53,2%
M(NaOH)=23+16+1=40
W(Na)=23/40=57,5%
W(O)=16/40=40%
W(H)=1/40=2,5%
M(SO2)=32+16*2=64
W(S)=32/64=50%
W(O)=(16*2)/64=50%
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Ответ:
24+32+16*4=120
Mg: 24/120 = 20%
S: 32/120 = 26,67%
O: 64/120 = 53,33%
Объяснение:
Ответ:
M(MgSO4)=24+32+16*4=120
W(Mg)=24/120=20,2%
W(S)=32/120=26,6%
W(O)=64/120=53,2%
M(NaOH)=23+16+1=40
W(Na)=23/40=57,5%
W(O)=16/40=40%
W(H)=1/40=2,5%
M(SO2)=32+16*2=64
W(S)=32/64=50%
W(O)=(16*2)/64=50%