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Fox00756
@Fox00756
July 2022
2
9
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Найти массовые доли элементов в аммиаке.
ДАНО: NH
3
НАЙТИ:
W(N)=?
W(H)=?
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Answers & Comments
sergivan
Mr(NH3)=Ar(N)+Ar(H)*3=14+1*3=17
w(N)=Ar(N) / Mr(NH3) =14/17=0.8235=82.35%
w(H)=Ar(H)*3 /Mr(NH3
) = 3/17=0.1764=17.65%
Ответ:w(N)=82.35%.w(H)=17.65%
0 votes
Thanks 0
VladaP
Verified answer
M(NH3)=14+3х1=17
W(N)=(14/17)х100%=82.4%
W(H)=(3/17)х100%= 17,6%
1 votes
Thanks 0
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Answers & Comments
w(N)=Ar(N) / Mr(NH3) =14/17=0.8235=82.35%
w(H)=Ar(H)*3 /Mr(NH3) = 3/17=0.1764=17.65%
Ответ:w(N)=82.35%.w(H)=17.65%
Verified answer
M(NH3)=14+3х1=17W(N)=(14/17)х100%=82.4%
W(H)=(3/17)х100%= 17,6%