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dozaradosti02
@dozaradosti02
November 2021
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Найти массу 18*10(в степени 23)молекул углекислого газа
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100ethereals
Verified answer
N(CO2)=N/N(A)=18*10^23/6,02*10^23=2,99 моль
m(CO2)=n(CO2)*M(CO2)=2,99*44=131,56 г.
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Verified answer
N(CO2)=N/N(A)=18*10^23/6,02*10^23=2,99 мольm(CO2)=n(CO2)*M(CO2)=2,99*44=131,56 г.