2HCl+Mg=MgCl2+H2
n(Mg)=0.3 моль
m(MgCl2)=n*M=28.5 г
V(H2)=n*Vm=6.72 дм3
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2HCl+Mg=MgCl2+H2
n(Mg)=0.3 моль
m(MgCl2)=n*M=28.5 г
V(H2)=n*Vm=6.72 дм3