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Ann44425
@Ann44425
July 2022
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Найти модуль вектора y=3a-b; a=(1;-2) b(-2;6).
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NNNLLL54
Verified answer
1 votes
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987oiu789
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↑3а(3;-6)
-↑b(2;-6)
↑y=↑3a+(-↑b); ↑y(5;-12)
|↑y|=√(5²+12²)=√169=13(единичных отрезков)
1 votes
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Answers & Comments
Verified answer
Verified answer
↑3а(3;-6)-↑b(2;-6)
↑y=↑3a+(-↑b); ↑y(5;-12)
|↑y|=√(5²+12²)=√169=13(единичных отрезков)